see it documented anywhere, but I was going to guess it's a logical shift.
Edited by jana, 23 May 2012 - 06:02 PM.
Right Shift Operator
Started by jana, May 23 2012 04:47 PM
4 replies to this topic
#1
jana
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Posted 23 May 2012 - 04:47 PM
Do computations with the right shift operator use a logical or arithmetic shift? I don't
see it documented anywhere, but I was going to guess it's a logical shift.
see it documented anywhere, but I was going to guess it's a logical shift.
#2
Zoltan Kriven
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Posted 23 May 2012 - 05:07 PM
Can you tell us why that is important, I'm more intermediate than advanced.Do computations with the right shift operator use a logical or arithmetic shift? I don't
see it documented anywhere, but I was going to guess it's a logical shift.
#3
TheouAegis
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Posted 23 May 2012 - 05:38 PM
Arithmetic I think.
If you mean "does it set the carry bit", then the answer is no from what I've seen. ... Seeing as how there's no built-in bitwise rotation function, I don't know how to go about testing it. It's just a simple floor(n/2) shift.
Edit: Sorry, my bad. I forgot about general terms. I haven't tested but that would be easy enough to test. Just take a negative number and apply a right-shift. If it stays negative, it's arithmetic. I'm at work so I can't test just now. But as far as the flooring, I'm pretty sure I saw it floor 3>>1 to 1.
If you mean "does it set the carry bit", then the answer is no from what I've seen. ... Seeing as how there's no built-in bitwise rotation function, I don't know how to go about testing it. It's just a simple floor(n/2) shift.
Edit: Sorry, my bad. I forgot about general terms. I haven't tested but that would be easy enough to test. Just take a negative number and apply a right-shift. If it stays negative, it's arithmetic. I'm at work so I can't test just now. But as far as the flooring, I'm pretty sure I saw it floor 3>>1 to 1.
Edited by TheouAegis, 23 May 2012 - 05:46 PM.
#4
jana
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Posted 23 May 2012 - 06:00 PM
Can you tell us why that is important, I'm more intermediate than advanced.
Do computations with the right shift operator use a logical or arithmetic shift? I don't
see it documented anywhere, but I was going to guess it's a logical shift.
It's important, because I'm checking out some code in C++ I might use, and it uses the right shift.
Edited by jana, 23 May 2012 - 06:00 PM.
#5
jana
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Posted 23 May 2012 - 06:01 PM
Arithmetic I think.
If you mean "does it set the carry bit", then the answer is no from what I've seen. ... Seeing as how there's no built-in bitwise rotation function, I don't know how to go about testing it. It's just a simple floor(n/2) shift.
Edit: Sorry, my bad. I forgot about general terms. I haven't tested but that would be easy enough to test. Just take a negative number and apply a right-shift. If it stays negative, it's arithmetic. I'm at work so I can't test just now. But as far as the flooring, I'm pretty sure I saw it floor 3>>1 to 1.
Thank you, you're right, I'll go test it.
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